# Schwarzschild metric: time coordinate

Reference: Moore, Thomas A., A General Relativity Workbook, University Science Books (2013) – Chapters 9; Problem 9.7.

The time component of the Schwarzschild metric does not correspond to proper time, even for an object at rest. This metric is, for a spherical mass ${M}$:

$\displaystyle ds^{2}=-\left(1-\frac{2GM}{r}\right)dt^{2}+\left(1-\frac{2GM}{r}\right)^{-1}dr^{2}+r^{2}d\theta^{2}+r^{2}\sin^{2}\theta d\phi^{2} \ \ \ \ \ (1)$

For an object at rest, the invariant interval is given by the proper time. That is, we assume that the relation from special relativity applies in curved space-time as well:

$\displaystyle ds^{2}=-d\tau^{2} \ \ \ \ \ (2)$

For the Schwarzschild metric, this means that for an object at rest:

 $\displaystyle \Delta\tau$ $\displaystyle =$ $\displaystyle \int\sqrt{-ds^{2}}\ \ \ \ \ (3)$ $\displaystyle$ $\displaystyle =$ $\displaystyle \int\left(1-\frac{2GM}{r}\right)^{1/2}dt\ \ \ \ \ (4)$ $\displaystyle$ $\displaystyle =$ $\displaystyle \left(1-\frac{2GM}{r}\right)^{1/2}\Delta t \ \ \ \ \ (5)$

The proper time interval for an object at rest is thus less than ${\Delta t}$ unless we are at an infinite distance from the mass. Note also that proper time appears to stop (in the sense that ${\Delta\tau=0}$) when ${r=2GM}$, which is the Schwarzschild radius.

The difference between ${t}$ and ${\tau}$ is difficult to visualize, and I’m not certain I really understand it. In his book, Moore describes an experimental setup in which a clock measuring ${\tau}$ and a ‘t-meter’ measuring ${t}$ are placed at a fixed point (fixed value of ${r}$). The clock measures proper time and we can calculate the reading on the t-meter from it by using the above equation. However, we can also measure ${t}$ by placing another clock at infinity, where ${\Delta t}$ and ${\Delta\tau}$ are equal. If we send a light signal once a second (as measured at infinity) from this clock towards the t-meter at ${r}$, then (ignoring the fact that if the distant clock is at infinity, it will take an infinite time to reach the t-meter) every time the t-meter receives a signal, it advances by 1 second. Since the light signal is travelling through curved space-time, its path isn’t the same as a light signal travelling through flat space-time. That is, if we removed the mass, thus making space-time flat, then the clock at ${r}$ and the t-meter at ${r}$ would agree. With the mass present, however, the time required by the light to reach the t-meter is increased since the light is following a curved path, so that the t-meter always says that a larger amount of time ${\Delta t}$ has elapsed than the interval ${\Delta\tau}$ measured by the proper time clock attached to the object.

Another way of looking at it is that if we release two light pulses separated by interval ${\Delta t_{A}}$ at ${r=r_{A}}$ and detect them at some other point where ${r=r_{B}}$, the interval ${\Delta t_{B}}$ measured by the detector will be the same as that at the source: ${\Delta t_{B}=\Delta t_{A}}$, although the proper time intervals that elapse at the source and detector will not be equal: ${\Delta\tau_{B}\ne\Delta\tau_{A}}$. It’s mind-bending stuff and I’m not sure how much benefit can be obtained by trying to visualize what’s going on intuitively; probably not much.

Here’s another example of a metric (fictitious as far as I know):

$\displaystyle ds^{2}=-dt^{2}+dr^{2}+R^{2}\sinh^{2}\frac{r}{R}\left(d\theta^{2}+\sin^{2}\theta d\phi^{2}\right) \ \ \ \ \ (6)$

For an object at rest here, the proper time and ${t}$ coordinate always agree, since

$\displaystyle ds^{2}=-d\tau^{2}=-dt^{2} \ \ \ \ \ (7)$

This metric describes a spherically symmetric space-time, since if we fix ${r=r_{0}}$ (and ${t=t_{0}}$) then ${dr=dt=0}$ and

$\displaystyle ds^{2}=R^{2}\sinh^{2}\frac{r_{0}}{R}\left(d\theta^{2}+\sin^{2}\theta d\phi^{2}\right) \ \ \ \ \ (8)$

That is, the metric has the form

$\displaystyle ds^{2}=K^{2}d\theta^{2}+K^{2}\sin^{2}\theta d\phi^{2} \ \ \ \ \ (9)$

for a constant ${K}$, which is the same as that of spherical coordinates for constant radius.

The meaning of the ${r}$ coordinate can be found by choosing a constant ${r=r_{0}}$ and ${t=t_{0}}$ at a fixed value of ${\theta=\frac{\pi}{2}}$. Then

$\displaystyle ds=R\sinh\frac{r_{0}}{R}d\phi \ \ \ \ \ (10)$

If we now integrate this through the range ${0\le\phi\le2\pi}$ we get the circumference ${C}$ of the equatorial circle:

$\displaystyle C=2\pi R\sinh\frac{r_{0}}{R} \ \ \ \ \ (11)$

The Taylor expansion of ${\sinh x}$ is

$\displaystyle \sinh x=x+\frac{x^{3}}{3!}+\frac{x^{5}}{5!}+\ldots \ \ \ \ \ (12)$

so for ${x>0}$, ${\sinh x>x}$. Therefore

$\displaystyle C>2\pi R\frac{r_{0}}{R}=2\pi r_{0} \ \ \ \ \ (13)$

Since a diagonal metric tensor means that the basis vectors are orthogonal, the fact that this metric is diagonal means the coordinate system is orthogonal.

## 11 thoughts on “Schwarzschild metric: time coordinate”

1. Chris Kranenberg

The difference between t and tau can possibly be visualized using Hartle’s description in Chapter 6 of Gravity. His flat world map, creating elongated lengths due to evenly spaced parallel longitudinal lines, describes the difference between t, an observer of the map making measurements between two points on the map, and tau, a traveler, such as an airline pilot, along a world line using a standard ruler.

2. Peter

MTW, in the section “Physical interpretation of Schwarzschild coordinates” – p596, appear to describe a similar setup to Moore’s “t-meter”. They also seem to be saying that one of the essential required properties of Schwarzschild coordinate time is that the metric coefficients do not change with respect to it, ie they are stationary. To quote from http://www.mathpages.com/home/kmath375/kmath375.htm: “the Schwarzschild time coordinate t has absolute physical significance in the sense that it is the essentially unique time coordinate in terms of which the metric coefficients (for a spherically symmetrical field) are stationary.”